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Excited to travel after the lockdown, pedro took a road trip along edsa. He is traveling 18. 0m/???? when he notices a red light ahead. His car is capable of a braking acceleration of 3. 65m/????2. Due to slow reaction, it takes him 0. 200 s to get the brakes on and he is 45. 0 m from the intersection when he sees the light. Due to slow reaction, how far did he travel to get the brakes on?.

Sagot :

Due to slow reaction, the distance he had to travel to get the brakes on is; 44.4 m

What is stopping Distance?

We are given;

Initial velocity; u = 0 m/s

Final Velocity; v = 18 m/s

Acceleration; a = 3.65 m/s²

Time; t = 0.2 s

To find the stopping distance, we will use newton's equation of motion to get;

v² = u² + 2a*d

Plugging in the relevant values gives us;

18² = 0² + 2(3.65d)

324 = 7.3d

d = 324/7.3

Stopping Distance; d = 44.4 m

Read more about Stopping Distance at; https://brainly.com/question/2087168

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