quinncampbell13
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if a gold atom is considered to be a cube with sides 2.5x10^-9m, how many gold atoms could stack on top of one another in gold foil with a thickness of 1.0x10^-7m?

Sagot :

hamzaahmeds

This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

NO. OF GOLD ATOMS THAT CAN STACK

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

  • 2.5 x 10⁻⁹ m  thick gold foil can stack = 1 gold atom
  • 1 m thick gold foil can stack = [tex]\frac{1}{2.5\ x\ 10^{-9}\ m}[/tex] gold atoms
  • 1 x 10⁻⁷ m  thick gold foil can stack = [tex]\frac{1\ x\ 10^{-7}\ m}{2.5\ x\ 10^{-9}\ m}[/tex] gold atoms
  • 1 x 10⁻⁷ m  thick gold foil can stack = 40 gold atoms

Learn more about thickness here:

https://brainly.com/question/177984

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