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How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Sagot :

MDKPfromIDN

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

Introduction

Hi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

[tex] \boxed{\sf{\bold{W = F \times s}}} [/tex]

With the following condition :

  • W = work (J)
  • F = force (N)
  • s = shift or displacement (m)

Now, the s (displacement) can be written as ∆h (altitude change) because the object move to vertical line. The formula can also be changed to:

[tex] \boxed{\sf{\bold{W = F \times \Delta h}}} [/tex]

With the following condition :

  • W = work (J)
  • F = force (N)
  • [tex] \sf{\Delta h} [/tex] = change of altitude (m)

If an object has mass, then the object will also be affected by gravity. Always remember that F = m × g. So that :

[tex] \sf{W = F \times \Delta h} [/tex]

[tex] \boxed{\sf{\bold{W = m \times g \times \Delta h}}} [/tex]

With the following condition :

  • W = work (J)
  • m = mass of the object (kg)
  • g = acceleration of the gravity (m/s²)
  • [tex] \sf{\Delta h} [/tex] = change of altitude (m)

Problem Solving

We know that :

  • F = force = 100 N
  • [tex] \sf{\Delta h} [/tex] = change of altitude 300 m

What was asked :

  • W = work = ... J

Step by step :

[tex] \sf{W = F \times \Delta h} [/tex]

[tex] \sf{W = 100 \times 300} [/tex]

[tex] \boxed{\sf{W = 30,000 \: J = 30 \: kJ}} [/tex]

Conclusion

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

See More :

  • Work that he had done to lift object https://brainly.com/question/26341717
  • Converting work to potential energy https://brainly.com/question/26487284
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