Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle: [tex]\frac{1}{2}[/tex]bh = [tex]\frac{1}{2}[/tex]⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
[tex]\frac{1}{2}[/tex]⋅4⋅5 = [tex]\frac{1}{2}[/tex]⋅20 = 10
Our area is 10 square units.
Hope that helps :)
