Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Hi there!
We can calculate linear momentum using the following:
[tex]\large\boxed{p = m v}[/tex]
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
Calculate:
[tex]p = 1000 * 20 = 20000 kg\frac{m}{s}[/tex]
Now, we can relate force, time, and momentum with the following:
[tex]\large\boxed{I = Ft}\\\\[/tex]
I = Impulse (kgm/s)
F = Force (N)
t = time (s)
Rearrange to solve for force:
[tex]F = \frac{I}{t}[/tex]
The impulse is equal to the change in momentum. Since the car comes to a halt, all of its momentum is lost, so:
[tex]I = \Delta p = p_f - p_i = 0 - 20000 = -20000[/tex]
Solve:
[tex]F = \frac{-20000}{0.5} = \boxed{-40000N}[/tex]
**Negative force since the positive direction is towards the wall, and the negative direction is away from the wall.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.