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94 passengers rode in a train from City A to City B. Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats cost ​281$. The receipts for the trip totaled 19,608​$. How many passengers purchased each type of​ ticket?

Sagot :

Using a system of equations, it is found that 41 regular and 53 sleeper seat tickets were sold.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Regular coach seats.
  • Variable y: Sleeper cars seats.

94 passengers rode in a train from City A to City B, hence:

[tex]x + y = 94[/tex]

Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats cost ​281$. The receipts for the trip totaled 19,608​$, hence:

[tex]115x + 281y = 19608[/tex]

From the first equation, x = 94 - y, hence, replacing on the second.

[tex]115x + 281y = 19608[/tex]

[tex]115(94 - y) + 281y = 19608[/tex]

[tex]166y = 8798[/tex]

[tex]y = \frac{8798}{166}[/tex]

[tex]y = 53[/tex]

[tex]x = 94 - y = 94 - 53 = 41[/tex]

Hence, 41 regular and 53 sleeper seat tickets were sold.

To learn more about system of equations, you can take a look at https://brainly.com/question/14183076