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The distance between Hadley and Greenville is 13 miles less than the distance between Parker and Greenville. Write two equations that compare the distance between Parker and Greenville. Tell what your variable represents.


Distance between Greenville and nearby Towns (Miles):


Parker: 29
Hadley: ?


Sagot :

x= Hadley
y= Parker
z= Greenville

 segment xz - 13 = segment zy

segment xz = segment zy + 13

Segment zy = 29 miles

Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles

Answer: [tex]x=y+13\\or\ x-y=13[/tex]

Here 'x' represents the distance between Hadley and Greenville   and 'y' represents  the distance between Parker and Greenville.

The distance between Hadley and Greenville =42 miles

Step-by-step explanation:

Let the distance between Hadley and Greenville  be x and the distance between Parker and Greenville be y.

Then according to the question,

[tex]x=y+13\\or\ x-y=13[/tex]

If the distance between Parker and Greenville = 29 miles

Then substitute the value of y=29 in the above equation, we get

[tex]x=29+13\\\Rightarrow\ x=42[/tex]

⇒ The distance between Hadley and Greenville =42 miles