Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
x= Hadley
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
Answer: [tex]x=y+13\\or\ x-y=13[/tex]
Here 'x' represents the distance between Hadley and Greenville and 'y' represents the distance between Parker and Greenville.
The distance between Hadley and Greenville =42 miles
Step-by-step explanation:
Let the distance between Hadley and Greenville be x and the distance between Parker and Greenville be y.
Then according to the question,
[tex]x=y+13\\or\ x-y=13[/tex]
If the distance between Parker and Greenville = 29 miles
Then substitute the value of y=29 in the above equation, we get
[tex]x=29+13\\\Rightarrow\ x=42[/tex]
⇒ The distance between Hadley and Greenville =42 miles
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.