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Sagot :
x= Hadley
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
Answer: [tex]x=y+13\\or\ x-y=13[/tex]
Here 'x' represents the distance between Hadley and Greenville and 'y' represents the distance between Parker and Greenville.
The distance between Hadley and Greenville =42 miles
Step-by-step explanation:
Let the distance between Hadley and Greenville be x and the distance between Parker and Greenville be y.
Then according to the question,
[tex]x=y+13\\or\ x-y=13[/tex]
If the distance between Parker and Greenville = 29 miles
Then substitute the value of y=29 in the above equation, we get
[tex]x=29+13\\\Rightarrow\ x=42[/tex]
⇒ The distance between Hadley and Greenville =42 miles
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