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If ƒ(x ) = x 2 + 1, find ƒ(a + 1).

Sagot :

luana
[tex]f(x)=x^2+1\\\\ f(a+1)=(a+1)^2+1=a^2+2a+1+1=a^2+2a+2\\\\ Solution\ is\ f(a+1)=a^2+2a+2[/tex]
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