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Sagot :
PE = mgh = (35)(9.8)(3.5) = answer
KE = (1/2)mv^2 = (1/2)(35)(5)^2 = answer
KE = (1/2)mv^2 = (1/2)(35)(5)^2 = answer
[tex]m=35kg\\\\h=3.5m\\\\v=5\ m/s\\\\g=10\ m/s^2\\\\E_p=mgh\\\\E_p=35kg\cdot10\ m/s^2\cdot3.5m=1225\ \frac{kgm^2}{s^2}=1225\ J\\\\E_k=\frac{mv^2}{2}\\\\E_k=\frac{35kg\cdot(5\ m/s)^2}{2}=\frac{35kg\cdot25\ m^2/s^2}{2}=437.5\ \frac{kgm^2}{s^2}=437.5\ J[/tex]
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