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Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.

Sagot :

SenorMathWiz

Answer:

2/6561

Step-by-step explanation:

Geometric sequence formula : [tex]a_n=a_1(r)^n^-^1[/tex]

where an = nth term, a1 = first term , r = common ratio and n = term position

given ratio : 1/3 , first term : 2 , given this we want to find the 9th term

to do so we simply plug in what we are given into the formula

recall formula : [tex]a_n=a_1(r)^n^-^1[/tex]

define variables : a1 = 2 , r = 1/3 , n = 9

plug in values

a9 = 2(1/3)^(9-1)

subtract exponents

a9 = 2(1/3)^8

evaluate exponent

a9 = 2 (1/6561)

multiply 2 and 1/6561

a9 = 2/6561

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