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What is the equation of the line that passes through the point (-2,-5) and has a slope of -3/2

Sagot :

LeCoolKid

Answer:

y = -3/2x - 8

Step-by-step explanation:

It is given to us that we have a slope of -3/2, and one of its points is (-2,-5)

So let's substitute the values in the equation y = mx + b to find b

-5 = -3/2(-2) + b

-5 = 3 + b

-3    -3

-8 =  b

b  =  -8

Now that we have b and m, we plug it into y = mx + b, getting y = -3/2x - 8

Comment if you have any questions! Your welcome :D

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