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What is an equation of the line that passes through the points (8,0) and (3,-5)?

Sagot :

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Recall that the general equation for a line is y=mx+b where m is the slope and b is the y-intercept.
First, let's find the slope by finding
(y2-y1)/(x2-x1):
(-8-0)/(-5-3)
-8/-8
1

Now we know the equation is y=1x+b, or y=x+b.
By plugging in one of the two points we know is on the line, we can solve for b.
0=3+b
b=-3

So the equation is:
y=x-3
  • (8,0)
  • (3,-5)

Slope:-

[tex]\\ \rm\hookrightarrow m=\dfrac{-5}{3-8}=-5/-5=1[/tex]

Equation of line in point slope form

[tex]\\ \rm\hookrightarrow y-y_1=m(x-x_1)[/tex]

[tex]\\ \rm\hookrightarrow y=x-8[/tex]

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