Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The properties of the quadrilaterals gives the equivalent relations used
to find the lengths and the angles.
Response:
1. m∠AED = 90°
2. m∠ADE = 23°
3. m∠BAE = 67°
4. AE = 5
5. BE = 12
6. 19
7. 22
8. WXYZ is a rectangle
9. WXYZ is a square
10. [tex]\overline{QS} \cong \overline{RT}[/tex] by Corresponding Parts of Congruent Triangles Congruent, CPCTC
11. a. The diagonals are perpendicular and the given figure is not a rectangle
b. The given figure is not a rhombus
c. The figure is a square.
d. ∠AEB = 90°
e. m∠EAD = 45°
Which properties of a quadrilateral can be used to find the required dimensions?
1. The diagonals of a rhombus bisect each other at right angles
Therefore;
m∠AED = 90° (by definition of right angles)
2. m∠EAD and m∠ADE are complementary angles
Which gives;
m∠EAD + m∠ADE = 90°
m∠ADE = 90° - m∠EAD
Therefore;
m∠ADE = 90° - 67° = 23°
3. The diagonals of a rhombus bisect the angles, therefore;
m∠BAE = m∠EAD = 67°
4. The diagonals bisect each other, therefore;
AE = CE = 5
5. BE = DE = 12
6. JL = 3·x + 4
KM = 4·x - 1
Which gives;
3·x + 4 = 4·x - 1
4·x - 3·x = 4 + 1 = 5
x = 5
KM = JL = 3 × 5 + 4 = 19
- The lengths of the diagonals of rectangle JKLM is 19
7. JL = 2·x - 6
[tex]KM = \mathbf{\dfrac{3}{2} \cdot x+ 1}[/tex]
Which gives;
[tex]\frac{3}{2} \cdot x+ 1 = 2\cdot x - 6[/tex]
[tex]2\cdot x -\frac{3}{2} \cdot x = 6 + 1 = 7[/tex]
[tex]\dfrac{1}{2} \cdot x = 7[/tex]
x = 2 × 7 = 14
JL = 2 × 14 - 6 = 22
- The lengths of the diagonals of rectangle JKLM are 22
8. W(3, 1), X(3, -2), Y(-5, -2), Z(-5, 1)
WX = 1 - (-2) = 3
YZ = 1 - (-2) = 3
XY = 3 - (-5) = 8
WZ = 3 - 5 = 8
Slope of WX = (1 - (-2)) ÷ (3 - 3) = ∞
Slope of YZ = (1 - (-2)) ÷ (-5 - (-5)) = ∞
Slope of XY = (-2- (-2)) ÷ (3- (-5)) = 0
Slope of WZ = (1- 1) ÷ (3- (-5)) = 0
Therefore;
WX and YZ are perpendicular to XY and WZ
The properties of WXYZ are the properties of a quadrilateral having perpendicular sides.
- Given that the sides are not equal, the figure is a rectangle
9. W(4, 1), X(1, 4), Y(-2, 1), Z(1, -2)
WX = √((4 - 1)² + (1 - 4)²) = 3·√2
YZ = √((1 - (-2))² + (-2 - 1)²) = 3·√2
XY = √((1 - (-2))² + (4 - 1)²) = 3·√2
WZ = √((1 - (-2))² + (4 - 1)²) = 3·√2
Slope of WX = (4 - 1) ÷ (1 - 4) = -1
Slope of YZ = (-2 - 1) ÷ (1 - (-2)) = -1
Slope of XY = (1 - 4) ÷ ((-2) - 1) = 1
Slope of WZ = (-2 - 1) ÷ (1 - 4) = 1
Therefore;
The lengths of the sides are equal and the sides are perpendicular to each other
Therefore;
- WXYZ is a square
10. The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
PSUR is a rectangle [tex]{}[/tex] Given
[tex]\overline{PR} = \overline{SU}[/tex] [tex]{}[/tex] Opposite sides of a rectangle
[tex]\overline{PQ} \cong \overline{TU}[/tex] [tex]{}[/tex] Given
[tex]\overline{PQ} = \overline{TU}[/tex] [tex]{}[/tex] Definition of congruency
[tex]\overline{PR} = \overline{RQ} + \overline{PQ}[/tex] [tex]{}[/tex] Segment addition postulate
[tex]\overline{SU} = \overline{ST} + \overline{TU}[/tex] [tex]{}[/tex] Segment addition postulate
[tex]\overline{RQ} = \overline{ST}[/tex] [tex]{}[/tex] Addition property of equality
ΔPQS ≅ ΔTUR [tex]{}[/tex] ASA rule of congruency
[tex]\overline{QS} \cong \overline{RT}[/tex] [tex]{}[/tex] CPCTC
11. The properties of a rectangle are;
The interior angles are 90°
The diagonals are not perpendicular to each other
In the given figure, the four triangles formed by the diagonals are congruent, therefore;
The angles at the vertex point of the four tringles are equal to each other and therefore, equal to 90°
Therefore;
- The diagonals are perpendicular and the given figure is not a rectangle
b. The lengths of the diagonals, are equal, therefore;
- The given figure is not a rhombus
e. The properties of the figure, which includes;
All sides are equal
The interior angles are 90°
- The diagonals are equal and bisect each other at 90° indicate that the figure is a square
d. The diagonals of a square are angle bisectors of the interior angles
Therefore;
m∠ABE = m∠CBE
m∠ABE + m∠CBE = 90° by definition of complementary angles
Therefore;
m∠ABE = 90° ÷ 2 = 45°
Similarly;
m∠ABE = m∠BAE = 45°
m∠AEB = 180° - (m∠ABE + m∠BAE)
- m∠AEB = 180° - (45° + 45°) = 90°
e. m∠EAD = m∠BAE = 45° (angles formed by the diagonal AC)
Learn more about quadrilaterals here:
https://brainly.com/question/12635945
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.