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PLEASE HELP!!
The length of a square is 4x-3, find the area in terms of x


Sagot :

Answer:

16[tex]x^{2}[/tex]−24x+9

Step-by-step explanation:

A=s^2

s=4x-3

A=(4x-3)^2

(a-b)^2=a^2-2ab+b^2

A=16x^2-2(12x)+9

A=16x^2-24x+9