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1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

A. One at a time
B. Two at a time
C. Seven at a time

2. In how many ways can three singers and four dancers be chosen to make a team if there are seven singers and ten dancers who are qualified?

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Sagot :

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

What is the combination formula?

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Exercise 1, item a:

One letter from a set of 7, hence:

[tex]C_{7,1} = \frac{7!}{1!6!} = 7[/tex]

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

[tex]C_{7,2} = \frac{7!}{2!5!} = 21[/tex]

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

[tex]C_{7,7} = \frac{7!}{0!7!} = 1[/tex]

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

[tex]T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245[/tex]

There are 245 ways to group them.

More can be learned about the combination formula at https://brainly.com/question/25821700