peachpaawz
Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A sample of oxygen at 40.°C occupies 820. mL. If this sample later occupies 1250 mL at 60.°C
and 1.40 atm, what was its original pressure?

Sagot :

indrawboy

[tex]\tt \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

T₁=40+273=313

T₂=60+273=333

P₁.820/313 = 1.4.1250/333

P₁=2.006 atm

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.