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Question 8 Calculate the volume at RTP occupied by: a) 0.16 g of oxygen ​

Sagot :

tiarateau04

Answer:

0.12 dm³ or 120 cm³

Explanation:

Hi there!

so first step find the number of moles

number of moles = mass ÷ Ar ( since o is an element and when it is alone, it is a diatomic molecule {O2} )

number of moles = mass ÷ Ar

number of moles = 0.16 ÷ ( 16 × 2 )

= 0.16 ÷ 32

= 5 × 10 ( power -3)

1 mol of O2 = 24 dm³ or 24 000 cm³

5 × 10 ( power -3) of O2 = (5 × 10 ( power -3)) × 24

= 0.12 dm³

or

= (5 × 10 ( power -3)) × 24 000

= 120 cm³

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