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I need help very quickly ! Worth 20 pts. Pls provide work attached that is eligible

I Need Help Very Quickly Worth 20 Pts Pls Provide Work Attached That Is Eligible class=

Sagot :

Check attached image

a) y = 9216

b) y = 360

Since x and y vary directly, y and x are directly related and can be expressed as y = kx. where k is a constant

y will increase as x increases. y will also decrease as x decreases.

I used k1 and k2 to separate the two questions and avoid confusion but using the constant k is fine.

a) For part a, you can substitute y = kx with the values of y and x.

[tex]1024 = k1 \times 9[/tex]

Hence, we can find the constant k1

[tex]k1 = \frac{1024}{9} [/tex]

Now, we can plug in the values into the original equation and obtain the new equation

[tex]y = \frac{1024}{9} x[/tex]

We can now solve part a by plugging in 81 into the value of x.

[tex]y = \frac{1024}{9} \times 81 = 9216[/tex]

b) Like part a, we can use the same method to find y for part b.

substitute y = kx with the values of y and x.

[tex]72 = k2 \times \frac{1}{2} [/tex]

Hence, we can find the constant k2

[tex]k2 = 72 \div \frac{1}{2} = 144[/tex]

Now, we can plug in the values into the original equation and obtain the new equation

[tex]y = 144x[/tex]

We can now solve part a by plugging in 5/2 into the value of x.

[tex]y = 144 \times \frac{5}{2} = 360[/tex]