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A wire loop having area 0.606 m2 is placed in a uniform magnetic field with the normal vector of the loop at a 75.1 degree angle to the field. The field has an initial magnitude of 2.91 Tesla and then is increased at a constant rate to 7.97 Tesla in 0.856 seconds. If a current of 0.0980 Amps is measured to flow through the wire during this time, what must the resistance of the wire be in Ohms

Sagot :

The resistance of the wire is is 36.55 ohms.

Induced emf of the coil

The induced emf in the loop is calculated by Faraday's law as follows;

emf = A(B₂- B₁)/t

emf = 0.606 (7.97 - 2.91)/0.856

emf = 3.58 V

Resistance of the wire

The resistance of the wire is calculated by using Ohms law as follows;

emf = IR

R = emf/I

R = 3.58/0.098

R = 36.55 ohms

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