Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
For the standard normal distribution, if P (z≤a) = 0. 7116, then the value of P(z≥a) is 0.2884.
What is Standard normal distribution?
The standard normal distribution is a special type of normal distribution where the mean is 0, and the standard deviation is 1.
As it is given that the value of P(z≤a)=0.7116, therefore, for P(z≤a) we can write,
[tex]P(z\leq a) = 0.7116\\\\P(z > a) =1- 0.7116\\[/tex]
But as we know the fact that in continuous distribution, the probability of a single point is 0, therefore, we can write
[tex]P(Z \leq z) = P(Z < z) )[/tex]
Similarly, for P(z>a)=0.7116 we can write,
[tex]P(z > a) = 1-0.7116\\\\P(z \geq a) = 1-0.7116\\\\P(z \geq a) = P(z=a) + P(z > a) = 1- 0+0.7116\\\\P(z \geq a) = 0.2884[/tex]
Hence, For the standard normal distribution, if P (z≤a) = 0. 7116, then the value of P (z≥a) is 0.2884.
Learn more about Standard normal distribution:
https://brainly.com/question/25447725
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
