Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
For the standard normal distribution, if P (z≤a) = 0. 7116, then the value of P(z≥a) is 0.2884.
What is Standard normal distribution?
The standard normal distribution is a special type of normal distribution where the mean is 0, and the standard deviation is 1.
As it is given that the value of P(z≤a)=0.7116, therefore, for P(z≤a) we can write,
[tex]P(z\leq a) = 0.7116\\\\P(z > a) =1- 0.7116\\[/tex]
But as we know the fact that in continuous distribution, the probability of a single point is 0, therefore, we can write
[tex]P(Z \leq z) = P(Z < z) )[/tex]
Similarly, for P(z>a)=0.7116 we can write,
[tex]P(z > a) = 1-0.7116\\\\P(z \geq a) = 1-0.7116\\\\P(z \geq a) = P(z=a) + P(z > a) = 1- 0+0.7116\\\\P(z \geq a) = 0.2884[/tex]
Hence, For the standard normal distribution, if P (z≤a) = 0. 7116, then the value of P (z≥a) is 0.2884.
Learn more about Standard normal distribution:
https://brainly.com/question/25447725
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
