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how do you get 1.8 from[tex]f(2)=\frac{2}{1+e^{-(2)} }[/tex]

Sagot :

Answer:

see explanation

Step-by-step explanation:

[tex]\frac{2}{1+e^{-2} }[/tex] ← evaluate [tex]e^{-2}[/tex] using calculator

= [tex]\frac{2}{1+0.135}[/tex]

= [tex]\frac{2}{1.135}[/tex]

= 1.762.....

≈ 1.8 ( to 1 dec. place )

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