Answer:
see attached diagram
Step-by-step explanation:
You have three functions with restricted domains:
f(x) = 3
f(x) = 2x + 1
f(x) = -2
We used a closed point for ≤ and ≥
and an open point for < and >
As the domain of f(x) = 3 is x ≤ -3
we add a closed point at (-3, 3) and then an arrow pointing towards the increasing negative (as x is equal to or less than -3)
As the domain of f(x) = -2 is x ≥ 4
we add a closed point at (4, -2) and then an arrow pointing towards the increasing positive (as x is equal to or greater than 4)
As the domain of f(x) = 2x + 1 is restricted to -3 < x < 4
we add open points at (-3, -5) and (4, 9) and then join them with a segment
