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Sagot :
Factorization is writing the expression in terms of multiplication of its factors. The given expression is prime(option A), thus, no factors.
What are prime polynomials?
Those polynomials with integer coefficients that cannot be factored further, with factors of lower degree and integer coefficients are called prime polynomial.
(it is necessary that no factors exists having their coefficients are still integers and they're of lower degree)
How to find the solution to a standard quadratic equation?
Suppose the given quadratic equation is
[tex]ax^2 + bx + c = 0[/tex]
Then its solutions are given as
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
Finding the roots of [tex]3x^2 - x + 5 =0[/tex], we get:
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \dfrac{1 \pm \sqrt{(-1)^2 - 4\times 5 \times 3}}{2 \times 3} = \dfrac{1 \pm \sqrt{1-60}}{6}[/tex]
Its square root is not real(if not using complex numbers, then its solution doesn't exist, making the roots non-real, and thus, polynomial not being able to get factorized. )
Learn more about prime polynomials here:
https://brainly.com/question/10717989
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