Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The magnitude of the electrostatic force between two point charges is f. If the distance between the charges is doubled, the electrostatic force between the charges will become.

Sagot :

When the  distance between the charges is doubled, the electrostatic force between the charges will reduce by quarter.

Electrostatic force between two point charges

The electrostatic force between two point charges is calculated using Coulomb's law;

[tex]F = \frac{kq^2}{r^2}[/tex]

where;

  • F is the force
  • k is Coulomb's constant
  • q is the charge
  • r is the distance

When the distance between the charges is doubled

[tex]F = \frac{kq^2}{(2r)^2} \\\\F = \frac{kq^2}{4r^2}\\\\F = \frac{1}{4} (\frac{kq^2}{r^2} )[/tex]

Thus, when the  distance between the charges is doubled, the electrostatic force between the charges will reduce by quarter.

Learn more about electrostatic force here: https://brainly.com/question/17692887

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.