Answered

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3.
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a
mass of 0.025 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a
collision with puck B, which has a mass of 0.050 kg and is initially at rest. The collision is
not head-on. After the collision the two pucks fly apart with the angles shown in the
drawing. Find the final speed of (a) puck A and (b) puck B. (Cutnell 7.30) 3.4 m/s, 2.6 m/s
+5.50

Sagot :

onyebuchinnaji

The final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.

Conservation of linear momentum

The final speed of the pucks is determined by applying the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.025(5.5) + 0.05(0) = 0.025v₁ + 0.05v₂

0.1375 = 0.025v₁ + 0.05v₂

One direction linear velocity

u₁ + v₁ = u₂ + v₂

5.5 + v₁ = 0 + v₂

v₁ = v₂ - 5.5

0.1375 = 0.025(v₂ - 5.5) + 0.05v₂

0.1375 = 0.025v₂ - 0.1375 + 0.05v₂

0.275 = 0.075v₂

v₂ = 0.275/0.075

v₂ = 3.7 m/s

v₁ = 3.7 - 5.5

v₁ = -1.8 m/s

Thus, the final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

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