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1 point
9. A 70 kg diver drops from a board 10 m above the water's surface.
Neglect air resistance. What is the diver's Kinetic Energy just before he hits
the water? Show work. NO work shown, NO credit. *
10.0 m
KE;= 0
PE;= mgyi
5.00 m
m
KE, = mv
PE, = 0
0
Your answer

Sagot :

asuwafohjames

The kinetic energy of the diver just before he hits the ground is 6860 J.



What is kinetic energy?

Kinetic energy can be defined as the energy of a body due to its motion.

Note: Just before the diver hits the ground, the potential energy is converted into kinetic energy.

Formula:

  • P.E(Potential energy) = K.E(Kinetic energy)
  • K.E = mgh..................... Equation 1

Where:

  • m = mass of the diver
  • h = height of the board
  • g = acceleration due to gravity.

From the question,

Given:

  • m = 70 kg
  • h = 10 m
  • g = acceleration due to gravity.

Substitute these values into equation 1

  • K.E = 70×10×9.8
  • K.E = 6860 J

Hence, The kinetic energy of the diver just before he hits the ground is 6860 J.

Learn more about kinetic energy here: https://brainly.com/question/25959744


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