This problem is asking for the solubility of CO2 at both 25. °C and 60. °C in different masses of water and that of KNO3 in 40. g of water at 80 °C. At the end, the answers are 0.14 g, 0.348 g and 68. g respectively.
In chemistry, solubility is defined as the maximum amount of a solute one can perfectly dissolve without getting any precipitate or undissolved amount.
In this case, for CO2, one can start seeing that at 25. °C its solubility in 1000 g of water is approximately 1.4 g, which means that in 100. g it turns out to be:
[tex]\frac{1.4gCO_2*100.gH_2O}{1000gH_2O} =0.14 gCO_2[/tex]
However, at 60. °C it is approximately 0.6 g in 1000 g of water, which means that in 580. g it turns out to be:
[tex]\frac{0.6gCO_2*580.gH_2O}{1000gH_2O} =0.348gCO_2[/tex]
Finally, since the solubility of KNO3 at 80 °C is about 170 g in 100 g of water, one can see that in 40. of water it turns out to be:
[tex]\frac{170 gKNO_3*40.gH_2O}{100gH_2O} =68 gKNO_3[/tex]
Learn more about solubility: https://brainly.com/question/13620168
