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7(2x+1/7)=14(3x-0.5)

pls and an explanation would help

Sagot :

fieryanswererft

answer:

[tex]\sf x = \frac{2}{7}[/tex]

solving steps:

[tex]\hookrightarrow \sf 7(2x+\frac{1}{7} )=14(3x-0.5)[/tex]

[tex]\hookrightarrow \sf 7(2x)+7(\frac{1}{7} )=14(3x)-14(0.5)[/tex]

[tex]\hookrightarrow \sf 14x + 1 = 42x - 7[/tex]

[tex]\hookrightarrow \sf 14x -42x = - 7-1[/tex]

[tex]\hookrightarrow \sf -28x = -8[/tex]

[tex]\hookrightarrow \sf x = \frac{-8}{-28}[/tex]

[tex]\hookrightarrow \sf x = \frac{2}{7}[/tex]

[tex]\\ \rm\hookrightarrow 7(2x+1/7)=14(3x-0.5)[/tex]

[tex]\\ \rm\hookrightarrow 2x+1/7=2(3x-0.5)[/tex]

[tex]\\ \rm\hookrightarrow 2x+1/7=6x-1[/tex]

[tex]\\ \rm\hookrightarrow 4x=1+1/7[/tex]

[tex]\\ \rm\hookrightarrow 4x=8/7[/tex]

[tex]\\ \rm\hookrightarrow x=8/28=2/7[/tex]

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