Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
(a) The height of the cliff will be 8.26 meters.
(b) The time would it take to reach the ground will be 0.717 sec.
What is velocity?
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
(a) The height of the cliff will be 8.26 meters.
According to Newton's second equation of motion
[tex]\rm H =ut-\frac{1}{2} gt^2 \\\\ \rm H =8\times 2.35-\frac{1}{2} 9.81 (2.35)^2\\\\\rm H =8.16 \; m[/tex]
Hence The height of the cliff will be 8.26 meters.
(b)The time would it take to reach the ground will be 0.717 sec.
We must have the final velocity to find the time so;
[tex]\rm v^2=u^2+2gh\\\\ \rm v^2=8^2+2\times 9.81 \times 8.6 \\\\ \rm v= \sqrt{8^2+2\times 9.81 \times 8.6}\\\\\rm v=15.03 \;m/sec[/tex]
According to Newton's third equation of motion ;
[tex]\rm v=u-gt \\\\ \rm t=\frac{v-u}{g} \\\\ \rm t=\frac{15.03-8}{9.81} \\\\ \rm t=0.717 sec.[/tex]
Hence the time would it take to reach the ground will be 0.717 sec.
To learn more about the velocity refer to the link ;
https://brainly.com/question/862972
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
