Answered

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Solve the following system of equations:
x+y+z=4
-3x-4y+4z=12
2x-y-4z=-1

Sagot :

kgirl633

Answer:

1) x=4-y-z

2) x=-12+4y-4z/3

3) x=-1+y+4z/2

Step-by-step explanation:

1) Subtract y+z from both sides.

x+y+z-(y+z)=4-(y+z)

Simplify

x=4-y-z

2) Subtract -4y+4z from both sides.

-4y+4z-(-4y+4z)=12-(-4y+4z)

Simplify

-3x=12+4y-4z

Divide both sides by -3

-3x/-3=12/-3+4y/-3-4z/-3

x=-12+4y-4z/3

3) Subtract -y-4z from both sides.

2x-y-4z-(-y-4z)=-1-(-y-4z)

Simplify

2x=-1+y+4z

Divide both sides by 2

2x/2=-1/2+y/2+4z/2

Simplify

x=-1+y+4z/2

Hope this helps! Pls give brainliest!

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