Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Probability, help, please

​

Probability Help Please class=

Sagot :

Problem 1

Answer: Choice A)  1/3

-------------------

Explanation:

The notation "P(tune-ups | AC repair)" is the same as saying "P(tune-ups given AC repair)".

The "given" means we only focus on the "AC repair" circle.

Add up the numbers in that circle to get: 1+3+2+0 = 6

There are 6 ASE certified mechanics that can do AC repair.

Of those 6 people, only 2+0 = 2 can do engine tune-ups. Note I added the values in the "AC repair" and "tune-ups" overlapped region.

Therefore, we get the probability 2/6 = 1/3

==========================================================

Problem 2

Answer:  B) 2/3

-------------------

Explanation:

First, we'll add the numbers found in either the "brakes" or "tune-ups" circles.

4+1+2+2+3+0 = 12

There are 12 mechanics that can handle brakes or tune-ups or both.

Now add up all of the numbers shown regardless of their location. We have 4+1+3+2+2+0+3+3 = 18 mechanics total.

So,

m = number who can do brakes or tune-ups or both

m = 12

n = number of mechanics total

n = 18

And,

P(brakes or tune-ups) = m/n

P(brakes or tune-ups) = 12/18

P(brakes or tune-ups) = (6*2)/(6*3)

P(brakes or tune-ups) = 2/3

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.