helenakpabio980
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construct a quadratic equation whose root are 2-√3 and 2+√3​

Sagot :

Step-by-step explanation:

A quadratic equation can be constructed from their roots,

[tex](x - p)(x - q)[/tex]

where p and q are the roots.

Here the roots are

[tex]2 - \sqrt{3} [/tex]

and

[tex]2 + \sqrt{3} [/tex]

So we have

[tex](x - (2 - \sqrt{3} ))(x - (2 + \sqrt{3} ))[/tex]

[tex] {x}^{2} - 2x - x \sqrt{3} - 2x + x \sqrt{3} + 4 - 3[/tex]

[tex] {x}^{2} - 4x + 1 = 0[/tex]

So our answer is x^2

[tex] {x}^{2} - 4x + 1 = 0[/tex]

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