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Sagot :
Taking into account the reaction stoichiometry, 90.33 grams of SO₂ are formed when 124 grams of iron(II) sulfide are used.
Reaction stoichiometry
In first place, the balanced reaction is:
4 FeS + 7 O₂ → 2 Fe₂O₃ + 4 SO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- FeS: 4 moles
- O₂: 7 moles
- Fe₂O₃: 2 moles
- SO₂: 4 moles
The molar mass of the compounds is:
- FeS: 87.85 g/mole
- O₂: 32 g/mole
- Fe₂O₃: 159.7 g/mole
- SO₂: 64 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- FeS: 4 moles ×87.85 g/mole= 351.4 grams
- O₂: 7 moles ×32 g/mole= 224 grams
- Fe₂O₃: 2 moles ×159.7 g/mole= 319.4 grams
- SO₂: 4 moles ×64 g/mole= 256 grams
Mass of sulfur dioxide formed
The following rule of three can be applied: if by reaction stoichiometry 351.4 grams of FeS form 256 grams of SO₂, 124 grams of FeS form how much mass of SO₂?
[tex]mass of SO_{2} =\frac{124 grams of FeSx256 grams ofSO_{2}}{351.4 grams of FeS}[/tex]
mass of SO₂= 90.33 grams
Then, 90.33 grams of SO₂ are formed when 124 grams of iron(II) sulfide are used.
Learn more about the reaction stoichiometry:
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