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Sagot :
[tex]\\ \rm\bull\rightarrowtail y=(1x^2)+3(x)[/tex]
[tex]\\ \rm\bull\rightarrowtail y=1(-6)^2+3(-6)[/tex]
[tex]\\ \rm\bull\rightarrowtail y=1(36)+(-18)[/tex]
Note the rule
- (+)(-)=(-)
[tex]\\ \rm\bull\rightarrowtail y=36-18[/tex]
[tex]\\ \rm\bull\rightarrowtail y=18[/tex]
Answer:
36 -18
18
Step-by-step explanation:
This is slightly confusing, since the question says "find the y coordinate if x = -4" yet underneath if appears they want x = -6 !
If x = -6
Substitute -6 into the equation in place of x
⇒ y = 1 × (-6)² + 3(-6)
Apply the rule (-a)² = a² and a(-b) = -ab:
⇒ y = 1 × (6)² + -3×6
⇒ y = 1 × 36 + -18
Using order of operations, carry out the multiplication first:
⇒ y = 36 + -18
Then the addition (subtraction)
⇒ y = 36 - 18
⇒ y = 18
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