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The two loops in (Figure 1) have equal currents in opposite directions. What current will create a magnetic field strength of 850 μT at the center?

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onyebuchinnaji

The current that will produce the given magnetic field strength is 4,250r ( r is the distance from the wire).

Magnetic field strength

The magnetic field strength at the center of the loop is calculated as follows;

B = (μ₀I)/(2πr)

where;

  • B is magnetic field strength
  • μ₀ is permeability of free space
  • I is the current
  • r is the distance from the wire

Solving for the current;

I = (2πrB)/(μ₀)

[tex]I = \frac{2\pi \times r \times 850 \times 10^{-6}}{4\pi \times 10^{-7}} \\\\I = 4,250 r[/tex]

Thus, the current that will produce the given magnetic field strength is 4,250r ( r is the distance from the wire).

Learn more about magnetic field strength here: https://brainly.com/question/20215216

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