Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

The number of pollinated flowers as a function of time in days can be represented by the function.
f(x)=(3)^(x/2)
What is the average increase in the number of flowers pollinated per day between days 4 and 10?
Enter your answer in the box.

Sagot :

christiand375

So in this case f(x) is number of pollinated flowers and x is the days. First you will need to determine the number of flowers pollinated at days 4 and 10 and the days in between.  f(4)= 3(4^2)= 3*16 = 48  f(5)= 3(5^2)= 3*25 =75  f(6)= 3(6^2)=3*36=108  f(7)= 3(7^2)=3*49=147  f(8)= 3(8^2)=3*64=192  f(9)= 3(9^2)= 3*81=243  f(10)= 3(10^2)=3*100=300    Now we need to find the average increase, so that will be the average of the differences between days  [(75-48)+(108-75)+(147-108)+(192-147)+(243-192)+(300-243)]/6  =(27+33+39+45+51+57)/6=42

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.