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Sagot :
STP (Standard Temperature and Pressure):
At STP, 1 mole of an ideal gas will occupy a volume of 22.4 liters (Note: the new defined STP volume is 22.7 liters).
The volume is 77 L .
3 moles of oxygen at STP will occupy a volume of 3×22. 4=67. 2 L.
1.5 moles of oxygen at stp = 22.4 x 1.5 = 33.6 litres.
Therefore , number of moles of oxygen is : Now , we know volume of 1 mole of gas at S.T.P is 22.4 liters . Therefore , volume of 0.1 mole of oxygen at S.T.P is : Therefore , the volume of 3.2 gram atom of oxygen at S.T.P is 2.24 liters .
Helium is the largest, so that’s going to have the largest volume. Because at STP, volume was going to be equivalent to moles of gas.
Therefore, chemists introduced the concept of molar volume. Molar volume of a gas is defined as the volume of one mole of the gas. Thus, the molar volume is also the volume occupied by 6.02 x 1023 particles of gas. The molar volume of any gas is 22.4 dm3 mol–1 at STP or 24 dm3 mol–1 at room conditions.
oxygen gas
One mole of oxygen gas occupies 22.4 l volume at STP.
67.2 liters
The answer depends on the temperature and pressure. If the gas is at STP, THE 1 mole is 22.4 liters. 3 moles x 22.4 L/mol = 67.2 liters.
Well, assuming that the hydrogen gas is contained at STP , then the molar volume would be 22.7⋅3=68.1 L .
0.5 moles⋅22.4 L/mol=11.2 L , and so on.
The molar volume of any gas at S.T.P. is 22.4L .
So, the volume of an ideal gas is 22.41 L/mol at STP. This, 22.4 L, is probably the most remembered and least useful number in chemistry.
At STP, one mol of Ideal Gas occupies 22.4 L and one mmol of Ideal Gas occupies 22.4 mL.
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