Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

If m∠jkl = (8x – 6)° and measure of arc jml = (25x – 13)°, find measure of arc jml.

Sagot :

akposevictor

Applying the angle of intersecting secants theorem, the measure of arc JML is: 262°.

What is the Angle of Intersecting Secants Theorem?

The angle of intersecting secants theorem states that when two lines form an external angle outside a circle, the measure of the angle is half the difference between the measure of the major and minor intercepted arcs.

Thus:

m∠JKL = (measure of arc JML - measure of arc JL)/2 => angle of intersecting secants theorem

m∠JKL  = 8x - 6

measure of arc JML = 25x - 13

measure of arc JL = 360 - (25x - 13)

Plug in the values

8x - 6 = [(25x - 13) - (360 - (25x - 13))/2]

Solve for x

2(8x - 6) = [(25x - 13) - (360 - 25x + 13)]

16x - 12 = [(25x - 13) - (373 - 25x)]

16x - 12 = 25x - 13 - 373 + 25x

16x - 12 = 50x - 386

16x - 50x = 12 - 386

-34x = -374

x = 11

Measure of arc JML = 25x - 13

Plug in the value of x

Measure of arc JML = 25(11) - 13 = 262°

Learn more about angle of intersecting secants theorem on:

https://brainly.com/question/1626547

View image akposevictor
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.