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Solve −79(x+3)=14 please help me answer

Sagot :

theleangreenbean

Answer:

[tex]x=-\dfrac{251}{79}[/tex]

Step-by-step explanation:

[tex]-79(x+3)=14[/tex]

To isolate x, we must perform inverse operations on both sides of the equal sign to cancel values out.

First, divide both sides by -79 to get rid of it on the left side of the equation:

[tex]\dfrac{-79(x+3)}{-79}=\dfrac{14}{-79}[/tex]

[tex]x+3=-\dfrac{14}{79}[/tex]

Now, subtract 3 from both sides to isolate x:

[tex]x+3-3=-\dfrac{14}{79}-3[/tex]

[tex]x=-\dfrac{14}{79}-3[/tex]

[tex]x=-\dfrac{251}{79}[/tex]

Amphitrite1040

Hey there!


-79(x + 3) = 14


DISTRIBUTE -79 WITHIN the PARENTHESES

-79(x) - 79(3) = 14
-79x - 273 = 14

ADD 273 to BOTH SIDES

-79x - 273 + 273 = 14 + 273

CANCEL out: -273 + 273 because it gives you 0

KEEP: 14 + 273 because it help solve for the x-value


NEW EQUATION: -79x = 14 + 273


SIMPLIFY IT!

-79x = 251


DIVIDE -79 to BOTH SIDES

-79x/-79 = 251/-79

CANCEL out: -79/-79 because it give you 1

KEEP: 251/-79 because it give you the x-value


NEW EQUATION: x = 251/-79


SIMPLIFY IT!

x = - 3 14/76 or x = - 251/79

Therefore, your answer is:
x = - 3 14/76 or x = - 251/79



Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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