futbolhombre20
Answered

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ABC has vertices at A(0,4),B(2,2) and C(–2,–1) what is the perimeter of ABC?

Sagot :

Medunno13

Answer:

Step-by-step explanation:

Using the distance formula,

[tex]AB=\sqrt{(0-2)^{2}+(4-2)^{2}}=2\sqrt{2}\\AC=\sqrt{(0-(-2))^{2}+(4-(-1))^{2}}=\sqrt{29}\\BC=\sqrt{(2-(-2))^{2}+(2-(-1))^{2}}=5[/tex]

So the perimeter is [tex]5+2\sqrt{2}+\sqrt{29}[/tex]

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