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What is the height of the cannon before it is launched, at t=0? Remember to include units.

Sagot :

The height of the cannon before it is launched, at t=0, is 58 m.

Model for the motion of the cannon ball

The equation of motion of the cannon ball is given as;

h(t) = -4.9t² + 19.8t + 58

Height of the cannon at time, t = 0

The initial height of the cannon before it was launched is calculated as follows;

h(0) = -4.9(0) + 19.8(0) + 58

h(0) = 58 m

Thus, the height of the cannon before it is launched, at t=0, is 58 m.

Complete question is below:

The equation that models the path of a cannon ball is  h(t) = -4.9t² + 19.8t + 58. What is the height of the cannon before it is launched, at t=0? Remember to include units.

Learn more about height of motion here: https://brainly.com/question/5687206

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