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Help me to answer this pls​

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Sagot :

Problem 1

x = measure of angle N

2x = measure of angle M, twice as large as N

3(2x) = 6x = measure of angle O, three times as large as M

The three angles add to 180 which is true of any triangle.

M+N+O = 180

x+2x+6x = 180

9x = 180

x = 180/9

x = 20 is the measure of angle N

Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.

Answers:

  • Angle M = 40 degrees
  • Angle N = 20 degrees
  • Angle O =  120 degrees

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Problem 2

n = number of sides

S = sum of the interior angles of a polygon with n sides

S = 180(n-2)

2700 = 180(n-2)

n-2 = 2700/180

n-2 = 15

n = 15+2

n = 17

Answer: 17 sides

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Problem 3

x = smaller acute angle

3x = larger acute angle, three times as large

For any right triangle, the two acute angles always add to 90.

x+3x = 90

4x = 90

x = 90/4

x = 22.5

This leads to 3x = 3*22.5 = 67.5

Answers:

  • Smaller acute angle = 22.5 degrees
  • Larger acute angle = 67.5 degrees
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