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How many grams of KNO3 should be used to prepare 2.00 L of a 0.500 M solution?

Sagot :

hunterhrbek

Answer:

101 g KNO₃

Explanation:

Molarity is measued in moles per liter, mol L− 1, or molar, M, which means that a 0.500-M solution will contain 0.500 moles of potassium nitrate for every 1 L of solution.

Well, if you get 0.500 moles for every liter of solution, and your solution has a total volume of 2.0 L, it follows that it must contain 2 × 0.500 moles = 1.00 moles KNO₃

So, what mass of potassium nitrate is equivalent to one mole of the compound?

Potassium nitrate's molar mass, 101.103 g mol− 1, tells you the mass of one mole of potassium nitrate. In this case, the answer must be rounded to three sig figs, so m KNO₃ = 101 g KNO₃

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