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find the 5 consecutive odd integers if the sum of the first integer is 7 more than the sum of the last 2

Sagot :

Answer: 15,17,19,21,23

Step-by-step explanation:

You can let the middle number = x, then the numbers are

x-4, x-2, x, x+2, x+4

Plugging it back in to what is given,

x-4+x-2+x = 7+x+2+x+4

3x-6 = 2x + 13

x = 19

The numbers are 15, 17, 19, 21, 23

Need points I have no idea what the answer is