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A line passes through the point (-5,-1) and has a slope of 4
write an equation in slope intercept form for this line

Sagot :

Hello.

We have a point that the line passes through:

[tex]\mathrm{(-5,-1)}[/tex]

We also have the line's slope:

[tex]\mathrm{4}[/tex]

Right now, we do not have enough information to write the equation of the line in slope-intercept form. We need to know the slope and the y-intercept. We do know the slope, but we do not know the y-intercept...yet.

We do have enough information to write the line's equation in Point-Slope Form:

[tex]\mathrm{y-y1=m(x-x1)}[/tex]

Plug in the values:

[tex]\mathrm{y-(-1)=4(x-(-5)}[/tex]

[tex]\mathrm{y+1=4(x+5)}[/tex]

Use the Distributive Property (a(b+c)=ab+ac) :

[tex]\mathrm{y+1=4x+20}[/tex]

Move 1 to the right:

[tex]\mathrm{y=4x+20-1}[/tex]

Subtract:

[tex]\mathrm{y=4x+19}[/tex]

Now we have the equation in slope-intercept form.

Therefore, the answer is

[tex]\mathrm{y=4x+19}[/tex]

I hope it helps.

Have a nice day.

[tex]\boxed{imperturbability}[/tex]

BasketballEinstein

Answer:

[tex]\displaystyle y = 4x + 19[/tex]

Step-by-step explanation:

Plug the information into the Slope-Intercept Formula like so:

[tex]\displaystyle y = mx + b \\ \\ -1 = 4[-5] + b \hookrightarrow -1 = -20 + b; 19 = b \\ \\ \\ \boxed{y = 4x + 19}[/tex]

I am joyous to assist you at any time.

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