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Sagot :
♪Answer :
»int 4x dx = ?
»(4/1 + 1)x¹+¹ + c
»4/2 x² + c
»2x² + c✅
[tex]\\ \rm\hookrightarrow {\displaystyle{\int}}4x dx[/tex]
[tex]\\ \rm\hookrightarrow 4(\dfrac{x^{1+1}}{2})[/tex]
[tex]\\ \rm\hookrightarrow 4x^2/2[/tex]
[tex]\\ \rm\hookrightarrow 2x^2[/tex]
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