Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Based on the data provided, at equilibrium, the concentration of Ni2+ that remains is 4.268 ×10^-6 M
What is molar concentration of a solution?
The molar concentration of a solution is the amount in moles of solute dissolved in a given volume of solution in litres.
- Molar concentration = moles/volume in Litres
Total volume of solution after mixing = 110 + 200 = 310 mL
Concentration of Ni2+ = 0.0133M/( 310ml/110ml) = 0.00472M
Concentration of NH3 = 0.250M/(310ml/200ml) = 0.1613 M
Assuming complete formation of Ni(NH3)6, the equation of formation is given as:
- Ni2+(aq) + 6NH3(aq) -------> Ni(NH3)62+ (aq)
From equation of the reaction, 1 mole of Ni2+ reacts with 6 moles of NH3 to produce 1 mole of Ni[(NH3)6]2+
Then,
0.00472 M of Ni2+ react with 0.02832 M of NH3 to give 0.00472 M of Ni2+
Concentration of remaining NH3 = 0.1613 M - 0.02832M = 0.13298 M
The equation of dissociation at equilibrium of Ni(NH3)62+ is given as:
- Ni[(NH3)6]2+(aq) <-------> Ni2+(aq) + 6NH3(aq)
Kd = [Ni2+][NH3]6/[Ni(NH3)6]
Kd = 1/Kf = 1/ 2.0 × 10^8
Kd = 5.0 ×10^-9
Using an ICE chart;
Initial concentration:
[Ni(NH3)62+] = 0.00472
[Ni2+] = 0
[NH3] = 0.
Change in concentration:
[Ni(NH3)62+] = - x
[Ni2+] = + x
[NH3] = + 6x
Equilibrium concentration:
[ Ni(NH3)62+] = 0.00472 - x
[Ni2+] = x
[NH3] = 0.13298 + 6x
From the dissociation constant equation;
x(0.1330 + 6x)^6 / 0.00472 - x) = 5.0 ×10^-9
Assuming x is very small;
- 0.13298 + 6x = 0.13298
- 0.00472 - x = 0.00472
x( 0.13298)^6/ 0.00472 = 5.0 ×10^-9
x × 0.00117= 5.0 ×10^-9
x = 4.268 ×10^-6 M
Therefore, at equilibrium, the concentration of Ni2+ that remains is 4.268 ×10^-6 M
Learn more about molar concentration at: https://brainly.com/question/26255204
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.