AimenKhan92
Answered

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the area of a trapezium with parallel sides 18cm 12cm and height is 8cm

Sagot :

ShiningSparkle

Trapezium

parallel sides = 18 cm, 12cm

Height = 8cm

____

Area of trapezium =

[tex] \frac{1}{2} \times (a + b) \times h[/tex]

____

[tex] \frac{1}{2} \times (a + b) \times h[/tex]

[tex] \frac{1}{2} \times (18 + 12) \times 8[/tex]

[tex] \frac{1}{2} \times (30) \times 8[/tex]

[tex] \frac{1}{1} \times (15) \times8[/tex]

[tex]120 \: cm ^{2} [/tex]

____

Therefore, Area of trapezium is [tex]120 \: cm {}^{2} [/tex]

Itz5151

Answer:

Area of Trapezium = 120 cm³

Step-by-step explanation:

Trapezium = 1/2 * (a+b) * h [Formulae]

A & b = Sum of parallel sides

Given that,

  • Height H = 8
  • Sum of parallel sides = 18 and 12, 18+12

Solved:

  • 1/2(18+12)8 cm²
  • 1/2 * 30 * 8 cm²
  • 15 * 8 cm²
  • 120 cm²

Therefore,the area of trapezium is 120 sq. cm or 120 cm².

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