Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Two water balloons were launched into the air at different moments and collided. The water balloons were modeled by the quadratic functions: y = −3x2 + 24x + 3 and y = −4x2 + 25x + 15, where y represents the height in meters and x represents the time in seconds after the launch. What is the time, in seconds, that the balloons collided at the highest point?

Sagot :

semsee45

Answer:

4s

Step-by-step explanation:

Equate the equations and solve for x:

[tex]-3x^2 + 24x + 3=-4x^2 + 25x + 15[/tex]

[tex]\implies x^2 -x -12=0[/tex]

[tex]\implies x^2 -4x+3x -12=0[/tex]

[tex]\implies x(x-4)+3(x-4)=0[/tex]

[tex]\implies (x+3)(x-4)=0[/tex]

[tex]\implies x=-3, x=4[/tex]

As time is positive, x = 4

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.