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IF YOU ANSWER FIRST ILL GIVE BRAINLY

What is the equation of the line that is parallel to 6x – 2y = 4 + 6y and passes through the point (8, –16)?

A. y=−43x−16/3
B. y=−3/4x−16
C. y=3/4x−22
D. y=4/3x−64/3

IF YOU ANSWER FIRST ILL GIVE BRAINLY What Is The Equation Of The Line That Is Parallel To 6x 2y 4 6y And Passes Through The Point 8 16 A Y43x163 B Y34x16 C Y34x class=

Sagot :

Izzy0l

Answer:

y=

4

3

x−22

Step-by-step explanation:

We are given;

The equation of a line 6x-2y=4+6y

A point (8, -16)

We are required to determine the equation of a line parallel to the given line and passing through the given point.

One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,

First we get the slope of the line from the equation given;

We write the equation in the form y = mx + c, where m is the slope

That is;

6x-2y=4+6y

6y + 2y = 6x-4

8y = 6x -4

We get, y = 3/4 x - 4

Therefore, the slope, m₁ = 3/4

But; for parallel lines m₁=m₂

Therefore, the slope of the line in question, m₂ = 3/4

To get the equation of the line;

We take a point (x, y) and the point (8, -16) together with the slope;

That is;

\frac{(y--16}{x-8}=\frac{3}{4}

x−8

(y−−16

=

4

3

\begin{gathered}4(y+16)=3(x-8)\\4y + 64 = 3x - 24\\4y=3x-88\\ y=\frac{3}{4}x-22\end{gathered}

4(y+16)=3(x−8)

4y+64=3x−24

4y=3x−88

y=

4

3

x−22

Thus, the equation required is y=\frac{3}{4}x-22y=

4

3

x−22

Answer:

C

Step-by-step explanation:

We are given;

The equation of a line 6x-2y=4+6y

A point (8, -16)

We are required to determine the equation of a line parallel to the given line and passing through the given point.

One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,

First we get the slope of the line from the equation given;

We write the equation in the form y = mx + c, where m is the slope

That is;

6x-2y=4+6y

6y + 2y = 6x-4

8y = 6x -4

We get, y = 3/4 x - 4

Therefore, the slope, m₁ = 3/4

But; for parallel lines m₁=m₂

Therefore, the slope of the line in question, m₂ = 3/4

To get the equation of the line;

We take a point (x, y) and the point (8, -16) together with the slope;

That is;

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